To declare an array in C++, the programmer specifies the type of the elements and the number of elements required by an array as follows − type arrayName [ arraySize ]; The source code from Where the Array Lurks shows a teensy program that declares an int array and then displays that array’s location in memory. &array is an alias for &array[0] and returns the address of the first element in array &pointer returns the address of pointer. If I have a pointer to some type and give the pointer address of an array, is it possible to display all of the elements instead of the first one only? This pointer also points to the first element of the array, but the type information is different (in the above example, the type of &array is int(*)[5]). When we pass the array in by its name, we are passing the address of the first array element. For example: Rectangle* baz = new Rectangle[2] { {2,5}, {3,6} }; displays both via hovering over the baz variable and in VARIABLES->Locals section. B) An array size must be declared if not initialized immediately. A) An array address is the address of first element of array itself. For this reason, the C programming language specifies that array indices always begin at 0; and many programmers will call that element " zeroth " rather than "first". C) Array size is the sum of sizes of all elements of the array. Thus, when we add one to it, the size of a single integer is added to it, giving us the second element. The expression, matrix[0], returns the address of the first element of the first row of the array. Declaring Arrays. R: Address of the first element of the array S: Address of every element of the array T: Swap the values of the array element by pointer operations U: Add all values of the array members using starting address of the array V: Find the different between the address of the first and last element of the array and try to calculate the memory occupied by this array #include
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